Java generics extends A or B

Jessie 95 Published: 12/03/2024

Java generics extends A or B

I'd be happy to explain how Java generics work when extending multiple types A and B.

In Java, generic classes can extend a single type using the extends keyword. For instance:

public class MyClass {

// code here...

}

Here, MyClass is a generic class that takes a type parameter T. The extends Number clause means that T must be a subclass of Number. This ensures that any value assigned to T must be a number (such as an integer, long, float, or double).

However, when you want to create a generic class that can extend multiple types, you can use interfaces. Here's how:

public interface A {

// methods and variables here...

}

public interface B {

// methods and variables here...

}

public class MyClass<T extends A & B> {

// code here...

}

In this example, MyClass is a generic class that can take types that implement both interfaces A and B. The & operator is called the "intersection" operator, which means "implement all of these interfaces". This ensures that any value assigned to T must be a class that implements both A and B.

This is useful when you have multiple interfaces that define common functionality, but the classes implementing those interfaces need to implement different sets of methods. For instance:

public interface Animal {

void makeSound();

}

public interface FlyingAnimal extends Animal {

void fly();

}

public class Bird implements Animal & FlyingAnimal {

@Override

public void makeSound() {

System.out.println("Chirp!");

}

@Override

public void fly() {

System.out.println("Winging it!");

}

}

In this example, the Bird class implements both Animal and FlyingAnimal interfaces. Because of Java's type inference rules, you can create an instance of Bird without explicitly specifying the interfaces:

public class Main {

public static void main(String[] args) {

Bird bird = new Bird();

// code here...

}

}

In this scenario, you wouldn't need to specify that bird implements both Animal and FlyingAnimal, because Java's type inference rules can figure it out. This makes your code more flexible and easier to maintain.

In summary, when creating a generic class in Java that extends multiple types, you can use interfaces with the intersection operator (&). This allows for more flexibility and expressiveness in your code.

What is the type meaning of the wildcard (?) In the context of Java generics?

In the context of Java generics, the wildcard ? represents a type that can match any reference or primitive type, including subclasses and subtypes. It's often referred to as the "unbounded" wildcard.

The ? wildcard is used in several scenarios:

Upper bound: When you want to specify a type that is a superclass of a specific type. For example:
public class Container {

private T value;

// ...

}

In this case, the type parameter T can be any subclass of Number, such as Integer, Double, or Long.

Lower bound: When you want to specify a type that is a subtype of a specific type. For example:
public class Container {

private T value;

// ...

}

In this case, the type parameter T can be any superclass of String, such as Object.

Wildcard in method parameters: When you want to create a method that can work with different types of objects, regardless of their actual class. For example:
public class Utility {

public static void processList(List list) {

for (T item : list) {

System.out.println(item);

}

}

}

In this case, the method processList can accept a List of any type T, and it will work correctly as long as you pass in a list containing objects that can be printed using System.out.println.

Wildcard in return types: When you want to create a method that returns an object that is a subtype or superclass of a specific type. For example:
public class Converter {

public static List convertCollection(Collection<? extends T> collection) {

List result = new ArrayList<>();

for (Object obj : collection) {

result.add((T) obj);

}

return result;

}

}

In this case, the method convertCollection takes a Collection of type ? extends T, which means it can accept any type that is a subclass of T. The method then returns a list of type T.

The ? wildcard provides great flexibility when working with Java generics. It allows you to define types that are flexible enough to work with different subclasses and subtypes, while still maintaining the benefits of generic programming.

In summary, the ? wildcard in Java generics represents a type that can match any reference or primitive type, including subclasses and subtypes. It's used to specify upper bounds, lower bounds, method parameters, and return types, allowing for flexible and reusable generic code.