Json serialization in java example

Cherry 89 Published: 09/18/2024

Json serialization in java example

Here is an example of JSON serialization in Java using the Jackson library:

Serialization Example

Let's say we have a simple Java class called Person:

public class Person {

private String name;


private int age;


public Person(String name, int age) {


this.name = name;


this.age = age;


}


public String getName() {


return name;


}


public int getAge() {


return age;


}


}

To serialize an instance of the Person class to a JSON string, we can use the following code:

import com.fasterxml.jackson.databind.ObjectMapper;

// Create an ObjectMapper instance


ObjectMapper mapper = new ObjectMapper();


// Create a Person object


Person person = new Person("John", 30);


// Serialize the Person object to a JSON string


String json = mapper.writeValueAsString(person);


System.out.println(json);

The output will be:

{"name":"John","age":30}

Deserialization Example

Now, let's say we have a JSON string that represents an instance of the Person class:

{"name":"Jane","age":25}

We can deserialize this JSON string back into a Person object using the following code:

// Deserialize the JSON string to a Person object

Person person = mapper.readValue(json, Person.class);


System.out.println(person.getName()); // prints "Jane"


System.out.println(person.getAge());   // prints 25

Using JsonNode

Jackson also provides a JsonNode class that allows us to work with the JSON data programmatically. We can use this class to extract specific values from the JSON string:

// Deserialize the JSON string to a JsonNode object

JsonNode node = mapper.readTree(json);


String name = node.get("name").asText();


int age = node.get("age").asInt();


System.out.println(name); // prints "Jane"


System.out.println(age);   // prints 25

Custom Serialization

By default, Jackson serializes objects to JSON using the object's public fields and getters. However, we can customize this behavior by implementing a custom JsonSerializer or JsonValue interface.

For example, let's say we want to serialize the Person class with a specific format:

public class PersonSerializer extends JsonSerializer {

@Override


public void serialize(Person person, JsonGenerator gen, SerializerProvider serializers) throws IOException {


gen.writeStartObject();


gen.writeStringField("full_name", person.getName());


gen.writeNumberField("age", person.getAge());


gen.writeEndObject();


}


}

We can then use this custom serializer to serialize the Person object:

// Create a custom ObjectMapper instance

ObjectMapper mapper = new ObjectMapper();


// Register the custom serializer for Person objects


mapper.setSerializationInclusion(JsonInclude.Include.ALWAYS);


mapper.setSerializerProvider(new SerializerProvider() {


@Override


public JsonSerializer findValueSerializer(Class<?> clazz) throws JsonProcessingException {


if (Person.class.isAssignableFrom(clazz)) {


return new PersonSerializer();


}


return super.findValueSerializer(clazz);


}


});


// Serialize the Person object to a JSON string using the custom serializer


String json = mapper.writeValueAsString(person);


System.out.println(json);



The output will be:


{"full_name":"John","age":30}

How to serialize an object into JSON in Java?

I apologize for the confusion earlier! Here's the answer:

Serializing an object into JSON in Java can be achieved through various libraries and frameworks. One popular way is by using Jackson, a high-performance JSON processor.

Here are the steps to serialize an object into JSON in Java using Jackson:

Step 1: Add Jackson Library to your Project

You can add Jackson library as a dependency in your project's build file (e.g., Maven or Gradle). For example, if you're using Maven, add the following dependency to your pom.xml file:



com.fasterxml.jackson.core


jackson-databind


2.11.1

Step 2: Create a POJO (Plain Old Java Object)

Create a simple Java class that represents the object you want to serialize:

public class User {

private String name;


private int age;


public User(String name, int age) {


this.name = name;


this.age = age;


}


// Getters and setters for name and age


}

Step 3: Use ObjectMapper to Serialize

Use the ObjectMapper class from Jackson library to serialize your POJO into a JSON string:

import com.fasterxml.jackson.databind.ObjectMapper;

public static void main(String[] args) throws JsonProcessingException {


User user = new User("John Doe", 30);


ObjectMapper mapper = new ObjectMapper();


String json = mapper.writeValueAsString(user);


System.out.println(json);


}

The writeValueAsString() method takes an object as input and returns a JSON string representation of that object. In this example, we pass our User object to the method, which serializes it into a JSON string.

Step 4: Parse JSON String Back into Java Object (Optional)

If you need to deserialize the JSON string back into a Java object, you can use the same ObjectMapper instance:

String json = "{"name":"John Doe","age":30}";

User user = mapper.readValue(json, User.class);


System.out.println(user.getName()); // prints "John Doe"


System.out.println(user.getAge()); // prints 30

In this example, we use the readValue() method to parse a JSON string into an object of type User. The second argument to the method specifies the target class for deserialization.

That's it! With these steps, you should be able to serialize your Java objects into JSON strings using Jackson library.

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